Skip to content
Login Register

#coordinates

3 public questions tagged with this topic.

Center of Mass and System of Particles

Two particles of masses 7kg and 3kg are at (0,6) and (5,0) respectively. What is the distance of their center of mass fr

X = (7×0)+(3×5)7+3 = 1510 = 1.5. Y = (7×6)+(3×0)7+3 = 4210 = 4.2. Distance = (1.5)2+(4.2)2 = 2.25+17.64 = 19.89≈4.46m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.46 m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details
Torque and Angular Momentum

A uniform circular ring of radius 2m and mass 5kg has its center at (3,4). What is the position of its center of mass?

For a uniform circular ring, the center of mass is at its geometric center. Given center at (3,4), CM position = (3,4). As per NCERT, applying relevant law/formula with correct units and sign convention leads to (3,4). This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details
Torque and Angular Momentum

A system of two particles, 3kg at (1,2) and 1kg at (5,6), moves as a rigid body. What is the distance of the center of m

X = (3×1)+(1×5)3+1 = 3+54 = 2. Y = (3×2)+(1×6)3+1 = 6+64 = 3. Distance = X2+Y2 = 22+32 = 4+9 = 13≈3.6m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details