Practice question
Question
A string of length 5 m and mass 0.05 kg is under a tension of 80 N. How long does a transverse pulse
take to travel its length?
Explanation
**Wave speed on string** is v = √(T/μ), T tension (N), μ = m/L linear mass density (kg/m). Higher T increases restoring force raising speed, heavier μ lowers speed. Frequency follows f = v/λ, linking mechanical properties to wave dynamics and harmonic series. Linear mass density: μ = (0.05/5) = 0.01 kg/m . Speed: v = √((T/μ)) = √((80/0.01)) = √(8000) ≈ 89.44 m/s . Time: t = (length/v) = (5/89.44) ≈ 0.056 s . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0.056 s, illustrating frequency-length-speed interdependence and quantization by boundaries.
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