Practice question
Question
A string of length 2.8 m and mass 0.07 kg has a fundamental frequency of 35 Hz. What is the tension in
the string?
Explanation
**Wave speed on string** is v = √(T/μ), T tension (N), μ = m/L linear mass density (kg/m). Higher T increases restoring force raising speed, heavier μ lowers speed. Frequency follows f = v/λ, linking mechanical properties to wave dynamics and harmonic series. μ = (0.07/2.8) = 0.025 kg/m . v₁ = (v/2L) ⇒ 35 = (v/2 × 2.8) ⇒ v = 35 × 5.6 = 196 m/s . v = √((T/μ)) ⇒ 196 = √((T/0.025)) ⇒ 196² = (T/0.025) . T = 38416 × 0.025 = 960.4 N . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable,
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