Practice question
Question
A string of length 2 m and mass 0.04 kg is under a tension of 100 N. What is the speed of a transverse
wave on the string?
Explanation
**Wave addition** governed by phase difference determines resultant intensity ∝ A². Phase arises from path difference Δ = (2π/λ)·Δx, and resultant formula captures interference condition quantitatively for NCERT problems. Linear mass density: μ = (0.04/2) = 0.02 kg/m . Speed: v = √((T/μ)) = √((100/0.02)) = √(5000) ≈ 70.71 m/s . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 70.7 m/s, illustrating frequency-length-speed interdependence and quantization by boundaries. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET and CUET.
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