Practice question
Question
A stone is thrown horizontally at 7m/s from a height of 31.25m. What is its time of flight? (Take g\=10m/s2)
Explanation
Vertical motion: y=12gt2, where y=−31.25m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 gt as the result, so option A is correct.
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