Practice question
Question
A square loop of side 25 cm rotates at 8 rad/s in a 0.15 T field. What is the maximum emf induced?
Explanation
Given:
A square loop of side 25 cm rotates at 8 rad/s in a 0.15 T field. What is the maximum emf induced?
These values define the system as per NCERT data.
Formula:
A = (0.25)² = 0.0625 m².
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
varepsilon_0 = N B A omega = 1 × 0.15 × 0.0625 × 8 = 0.075 V .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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