Practice question

Given: A spring system has m = 3 kg, k = 1200 N/m, A = 5 cm . What is the potential energy at x = 2.5 cm ? These values define the system as per NCERT data. Formula: Potential energy: U = 1/2 k x². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: k = 1200 N/m, x = 0.025 m . U = 0.5 × 1200 × (0.025)² = 0.5 × 1200 × 0.000625 = 0.375 J . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.