Practice question

**Energy distribution** shows maximum kinetic at equilibrium and maximum potential at extremes, sum constant. This relation enables calculation of amplitude, velocity at any displacement via v = ±√(2(E-U)/m), and understanding of energy storage in oscillating system for NEET problems. Potential energy: U = (1/2) k x² . k = 100 N/m, x = 0.04 m . U = 0.5 × 100 × (0.04)² = 0.5 × 100 × 0.0016 = 0.08 J . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.08 J follows, reflecting SHM dependence on amplitude A, ω and system parameters.