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Question

A spring of \( k = 300 \, \text{N/m} \) has a \( 1.5 \, \text{kg} \) mass. If \( E = 0.75 \, \text{J}
\), what is the amplitude?

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Explanation

**Energy in SHM** interconverts between kinetic K = ½ m v² = ½ m ω² (A² - x²) and potential U = ½ k x² = ½ m ω² x², total E = K + U = ½ k A² = ½ m ω² A² constant, independent of time. At mean position x=0, E = K_max = ½ m ω² A², at extremes x=±A, E = U_max = ½ k A². Total energy: E = (1/2) k A² . 0.75 = 0.5 × 300 × A² ⇒ 0.75 = 150 A² ⇒ A² = 0.005 ⇒ A = √(0.005) ≈ 0.071 m . Applying x

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