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Question

A solenoid produces \( B = 0.6 \, \text{T} \) with a core of \( \mu_r = 200 \) and \( n = 1000 \,
\text{m}^{-1} \). What is the current \( I \)? (Take \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1}
\)).

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Explanation

**Magnetic field inside solenoid** with core B = μ₀ μ_r n I is uniform, direction along axis given by right-hand grip rule. For n = 2000 m⁻¹, μ_r = 400, B = 1.2 T, I = 1.2/(4π×10⁻⁷×400×2000) ≈ 1.19 A, showing modest current produces tesla-level field with high μ_r core. B = μ₀ μ_r n I , so I = (B/μ₀ μ_r n) . Given: B = 0.6 T , μ_r = 200 , n = 1000 m⁻¹ , μ₀ = 4π × 10⁻⁷ . I = (0.6/4π × 10⁻⁷ × 200 × 1000) = (0.6/2.513 × 10⁻¹) ≈ 2.39 A ≈ 2.4 A .

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