Practice question
Question
A dipole with \( m = 0.7 \, \text{A m}^2 \) in \( B = 0.6 \, \text{T} \) at \( 30^\circ \) has torque:
Explanation
**Core magnetization** M = (μ_r -1)nI, so B = μ₀(nI + M). High μ_r materials like soft iron increase B dramatically for same nI, used in electromagnets, with μ_r up to 5000, enabling strong fields with low current. tau = m B sinθ . Given: m = 0.7 A m² , B = 0.6 T , θ = 30° , sin 30° = 0.5 . tau = 0.7 × 0.6 × 0.5 = 0.21 N m . Substituting values gives 0.21 N m, which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.
Discussion
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