Practice question
Question
A reaction has k = 6.0 × 10â»â¶ s^{-1 at 300 K and E_a = 50 kJ mol^{-1 . What is the pre-exponential factor A in s^{-1 ? (R = 8.314 J/mol · K)
Explanation
Given:
A reaction has k = 6.0 × 10â»â¶ s^{-1 at 300 K and E_a = 50 kJ mol^{-1 . What is the pre-exponential factor A in s^{-1 ? (R = 8.314 J/mol · K)
These values define the system as per NCERT data.
Formula:
k = A e^{-E_a/RT.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
6.0 × 10â»â¶= A e^{-50000/(8.314 × 300), A = 6.0 × 10â»â¶/ e^{-20.06 = 3.2 × __10POW₃__.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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