Practice question
Question
A particle moves under a force F\=4i^−2j^N along a displacement d\=3i^+6j^m. What is the work done by the force?
Explanation
Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 0 J. Work-energy theorem W=ΔK confirms. So option A is correct.
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