Practice question

**Velocity and acceleration in SHM** follow from differentiation, showing 90° phase lead of v over x and 180° for a over x. At mean position x=0, a=0, v=±ωA maximum; at extremes x=±A, v=0, a=∓ω²A maximum magnitude, illustrating energy conversion. Maximum velocity: vₘₐₓ = A ω . ω = 2π v = 2 × 3.14 × 3 = 18.84 rad/s . A = 0.06 m . vₘₐₓ = 0.06 × 18.84 = 1.1304 m/s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 1.1304 m/s follows, reflecting SHM dependence on amplitude A, ω and system parameters.