Practice question
Question
A mass oscillates with \( v = -10 \sin (5t) \) (in m/s). What is its amplitude?
Explanation
**SHM kinematics** given by x = A cos(ωt + φ), velocity v = dx/dt = -ω A sin(ωt + φ), acceleration a = dv/dt = -ω² A cos(ωt + φ) = -ω² x, maxima v_max = ωA at mean position x=0, a_max = ω²A at extremes x=±A. Phase φ determines initial position, ω = 2π/T = √(k/m). Velocity: v = -ω A sin (ω t) . ω = 5 s⁻¹, vₘₐₓ = ω A = 10 ⇒ A = (10/5) = 2 m . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² =
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