Practice question

**Parallel plate capacitor** capacitance C = ε₀ A/d, ε₀=8.85×10⁻¹² F/m, A plate area (m²), d separation (m), for air, with dielectric C = K ε₀ A/d. For A=0.08 m², d=0.4 mm=4×10⁻⁴ m, C=8.85×10⁻¹²×0.08/4×10⁻⁴=1.77×10⁻⁹ F=1.77 nF, illustrating small capacitance for cm separation. Potential difference: V = E₀ ( (3d/4) ) + (E₀/K) ( (d/4) ) = E₀ d ( (3/4) + (1/4 × 4) ) = E₀ d ( (3/4) + (1/16) ) = E₀ d × (13/16) . C = (Q/V) = (Q/(13/16) V₀) = (16/13) × 60 ≈ 73.85 pF . Using V = kQ/r, U = k q₁q₂/r, E = -dV/dr, C =