Practice question

**Capacitance depends on geometry** not charge, C = Q/V constant for given arrangement. Parallel plate C ∝ A/d, so larger area and smaller separation increase capacitance, principle used to increase storage by using large area foils with thin dielectric. For large parallel plates with charges +sigma and -sigma , the field between them is E = (sigma/ε₀) , uniform due to symmetry. A dielectric coating on one plate polarizes, inducing bound charges, but does not alter the free charge on the plates. The net field between the plates remains determined by the free charge density sigma , and the uniformity is preserved by the geometry,