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Question

A mixture of 2 moles of helium and 3 moles of nitrogen is at 400 K in a 50-litre container. What is the total pressure? (R = 8.31 J mol⁻¹ K⁻¹)

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Explanation

**Specific heat relation** C_p - C_v = R for ideal gas per mole, Mayer's relation, due to work done at constant pressure, degrees of freedom include translational, rotational, vibrational, each quadratic term contributes ½ R to C_v. PV = μ R T, P = (μ R T)/(V).Total moles = 2 + 3 = 5, V = 50 × 10⁻³ m³.P = (5 × 8.31 × 400)/(50 × 10⁻³) = 3.324 × 10⁵ Pa ≈ 3.32 atm. Substituting values gives 3.32 atm, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V = n R

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