Practice question
Question
A material has \( B = 0.54 \, \text{T} \) and \( M = 4.0 \times 10^5 \, \text{A m}^{-1} \). What is \(
H \)? (Take \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1} \)).
Explanation
**Torque on magnetic dipole** in uniform field B is τ = m × B, magnitude τ = m B sinθ, m moment (A·m²), B field (T), θ angle between m and B (degrees). Torque tends to align moment with field, zero at θ = 0°, maximum mB at 90°, direction given by right-hand rule. B = μ₀ (H + M) , so H = (B/μ₀) - M . Given: B = 0.54 T , M = 4.0 × 10⁵ A m⁻¹ , μ₀ = 4π × 10⁻⁷ . (B/μ₀) = (0.54/4π × 10⁻⁷) ≈ 4.297 × 10⁵ A m⁻¹ . H = 4.297 × 10⁵
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