Practice question
Question
A first-order reaction has a half-life of 35 minutes. What fraction of the reactant remains after 70 minutes?
Explanation
Given:
A first-order reaction has a half-life of 35 minutes. What fraction of the reactant remains after 70 minutes?
Formula:
k = 0.693/35 = 0.0198 min^{-1.
Substitution & Calculation:
ln frac[R]_0[R] = 0.0198 × 70 = 1.386, frac[R][R]_0 = e^{-1.386 = 0.25 .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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