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Question

A copper cube of edge length 0.1 m is subjected to a hydraulic pressure of 5 × 106 N/m2. If the bulk modulus of copper is 1.4 × 1011 N/m2, what is the change in volume?

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Explanation

Bulk modulus: B = -p / (ΔV / V). Volume: V = (0.1)3 = 0.001 m3. Fractional change: ΔV / V = -p / B = -(5 × 106) / (1.4 × 1011) ≈ -3.57 × 10-5. Change in volume: ΔV = (ΔV / V) × V = -3.57 × 10-5 × 0.001 ≈ -3.57 × 10-8 m3.

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