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Question

A conducting sphere of radius 27 cm has an electric field of \( 6 \times 10^3 \, \text{N/C} \) at 54 cm
from its center. What is the charge?

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Choose one · Correct answer highlighted

Explanation

**Fundamental property of charge** includes additivity and quantization, meaning net charge equals algebraic sum of constituents and each is multiple of e. When rod loses charge, electron removal is inferred, and n = q/e gives transferred count. E = (k q/r²) . 6 × 10³ = 9 × 10⁹ × (q/(0.54)²) . q = (6 × 10³ × 0.2916/9 × 10⁹) = 1.944 × 10⁻⁷ C . Substituting values gives 1.944 × 10⁻⁷ C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

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