Practice question
Question
A coil of self-inductance 0.4 H has its current decreased from 5 A to 2 A in 0.1 s. What is the
magnitude of the induced emf?
Explanation
**Flux change example** coil 150 turns area 0.06 m² B 0.14 T drops to zero in 0.3 s, ΔΦ = B A =0.14×0.06=0.0084 Wb per turn, ΔΦ/Δt=0.028 Wb/s, e=150×0.028=4.2 V, illustrating calculation from B and area. ε = -L (Δ I/Δ t) . Δ I = 2 - 5 = -3 A , Δ t = 0.1 s . ε = 0.4 × (-3/0.1) = 0.4 × (-30) = -12 V . Magnitude = 12 V. Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M
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