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Question

A wheel with 10 spokes of 0.7 m each rotates at 60 rpm in a 0.5 T field. What is the induced emf?

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Explanation

**Magnetic flux** Φ = B·A = B A cosθ, B magnetic field (T), A area (m²), θ angle between B and normal to area, unit Wb = T·m², Faraday's law induced emf e = -N dΦ/dt, N turns, negative sign Lenz's law indicating opposition, magnitude |e| = N |ΔΦ/Δt|, for 100 turns ΔΦ=0.03 Wb Δt=0.06 s e=100×0.03/0.06=50 V. ω = 2π × (60/60) = 2π rad/s . ε = (1/2) B ω R² = (1/2) × 0.5 × 2π × (0.7)² = 0.7697 V ≈ 0.77 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l

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