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Question

A chemostat is operated at a dilution rate of 0.6 h-1. At steady state, the biomass concentration in the exit stream was found to be 30 g l-1. The biomass productivity (g l-1h-1) after 3h of steady state operation will be ___________

Explanation

At steady state, biomass productivity =D×X =0.6×30=18 g L⁻¹ h⁻¹. After 3 hours, same rate persists because steady state maintains constant concentration, showing chemostat productivity depends on dilution and biomass, not elapsed time after equilibrium.

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