Skip to content

Question

A capillary tube of radius 0.25mm is dipped in ethanol (S\=0.0227N/m, ρ\=806kg/m3, cos⁡θ\=1). What is the capillary rise? (Take g\=9.8m/s2)

Options

Choose one · Correct answer highlighted

Explanation

h = 2Scos⁡θρga. S = 0.0227N/m, ρ = 806kg/m3, g = 9.8m/s2, a = 0.25×10−3m. h = 2×0.0227×1806×9.8×0.25×10−3 = 0.02298m = 2.3cm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.3 cm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Discussion

Comments

0 comments

Share your thoughts. New comments appear after admin approval.

No comments yet. Be the first to start the discussion.