Practice question
Question
A body loses 3.2 × 10⁻⁸C of charge when rubbed. How many electrons were transferred from it?
Explanation
Given:
A body loses 3.2 × 10⁻⁸C of charge when rubbed. How many electrons were transferred from it?
Formula:
q = n e, e = 1.6 × 10⁻¹⁹C.
Substitution & Calculation:
Losing charge means electrons are removed, so charge is positive. . n = q/|e| = frac3.2 × 10⁻⁸¹.6 × 10⁻¹⁹= 2 × 10¹¹.
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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