Practice question
Question
A body is launched from Earth at 12km/s. What is its speed at infinity? (Escape speed = 11.2km/s)
Explanation
vf2 = vi2−ve2. vf2 = (12)2−(11.2)2 = 144−125.44 = 18.56. vf = 18.56≈4.31km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.3 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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