Practice question
Question
A body is launched from Earth at 15.5km/s. What is its speed at infinity? (Escape speed = 11.2km/s)
Explanation
vf2 = vi2−ve2. vf2 = (15.5)2−(11.2)2 = 240.25−125.44 = 114.81. vf = 114.81≈10.71km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10.7 km/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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