Practice question
Question
A \( 8 \, \Omega \) resistor carries a current of \( 2.5 \, \text{A} \) for \( 10 \, \text{s} \). What
is the energy dissipated?
Explanation
**Power dissipation** in resistor converts electrical energy to heat, P = V²/R inversely proportional to R for fixed V, directly proportional for fixed I. For battery with internal r, power wasted internally = I² r, useful power = I² R, efficiency η = R/(R+r). Energy: W = I² R t . Substitute: W = (2.5)² × 8 × 10 = 6.25 × 80 = 500 J . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 500 J,
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