Practice question
Question
A \( 6 \, \Omega \) resistor carries a current of \( 3 \, \text{A} \) for \( 30 \, \text{s} \). What is
the energy dissipated?
Explanation
**Electrical power** P = V I = I² R = V²/R (W), energy E = P t = I² R t (J), heating effect Joule's law H = I² R t. When internal r equals external R, total resistance 2R, I = ε/2R, power in external = I²R = ε²/4R, total = ε²/2R, fraction external = 1/2, illustrating maximum power transfer when R = r. Energy: W = I² R t . Substitute: W = 3² × 6 × 30 = 9 × 180 = 1620 J . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0,
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