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Question

A \( 8 \, \Omega \) resistor carries a current of \( 2 \, \text{A} \) for \( 15 \, \text{s} \). What is
the energy dissipated?

Options

Choose one · Correct answer highlighted

Explanation

**Heating effect** depends on I² R t, explaining why high currents cause significant heating, need for thick wires, fuses. Energy supplied by battery ε I t = I²(R+r)t, split between external and internal as per resistances. Energy: W = I² R t . Substitute: W = 2² × 8 × 15 = 4 × 120 = 480 J . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 480 J,

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