Practice question
Question
A 4kg particle moves with velocity v\=5j^m/s at r\=−3i^m. What is the magnitude of its angular momentum about the origin?
Explanation
L = r×p = |i^j^k^−300050| = k^((−3)×5−0×0) = −15k^kg m2/s. Magnitude = 15kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 15 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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