Practice question

Given: A body weighs 196 N on Earth’s surface. What is its weight at a depth d = R_E/3 ? ( g = 9.8 m/s² ) These values define the system as per NCERT data. Formula: g(d) = g (1 - d/R_E). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: d = R_E/3, g(d) = 9.8 (1 - 1/3) = 9.8 × 2/3 = 6.53 m/s² . Mass: m = 196/9.8 = 20 kg . Weight: W = 20 × 6.53 approx 130.6 N . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.