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Question

An electromagnetic wave has a wave number \( k = 3 \, \text{rad/m} \). What is its wavelength in
vacuum?

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Explanation

**Ultraviolet** λ≈10-400 nm, produced by atomic transitions and Sun, causes fluorescence, sterilization, harmful to eyes/skin, absorbed by ozone layer. **X-rays** λ≈10⁻² to 10 nm, produced by rapid deceleration of energetic electrons in X-ray tube, used in medicine for diagnosis (shadow of bones) and cancer therapy due to high ionization and penetration, detected by photographic film and Geiger counter. The wave number k = (2 π/λ) . Given k = 3 rad/m , we have λ = (2 π/k) = (2 π/3) ≈ 2.09 m . Using c = fλ, E₀/B₀ = c, I_d = ε₀ dΦ_E/dt, and spectrum classification λ = c/f, evaluation yields 2.09

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