Practice question

Given: A coil of 80 turns is placed in a magnetic field that increases from 0 to 0.03 Wb/m² in 0.2 s. If the coil area is 0.05 m², what is the induced emf? These values define the system as per NCERT data. Formula: Flux change: Δ Phi = B A = 0.03 × 0.05 = 0.0015 Wb. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: varepsilon = N Δ Phi/Δ t = 80 × 0.0015/0.2 = 80 × 0.0075 = 0.6 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.