Practice question

At the surface. Above, g decreases with 1/(RE+h)2; below, only inner mass contributes, reducing g linearly as g(d) = g(1−d/RE). Thus, g peaks at r = RE. As per NCERT, applying relevant law/formula with correct units and sign convention leads to All mass contributes at the surface. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.