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Question

Why does the voltage across the inductor in a series LCR circuit equal the voltage across the capacitor
at resonance, despite their phase difference?

Options

Choose one · Correct answer highlighted

Explanation

**At resonance** V_L = I X_L = I X_C = V_C, may be larger than source voltage Q times, Q-factor = ω₀ L/R =1/(ω₀ C R)= V_L/V = V_C/V, measures sharpness, higher Q sharper resonance, bandwidth Δω = R/L = ω₀/Q, resonant frequency independent of R. At resonance, X_L = X_C , and since V_L = I X_L and V_C = I X_C with the same current I , their magnitudes are equal. However, they are 180° out of phase, so their vector sum is zero, not their magnitudes. Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms =

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