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Question

Why does a superconductor exhibit zero resistance below its critical temperature?

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Explanation

**Wheatstone bridge balance** condition R₁/R₂ = R₃/R₄, R₄ = R₂ R₃/R₁, when galvanometer current zero, potentials at midpoints equal. At balance, no current through galvanometer, enabling precise resistance measurement independent of source voltage. Below the critical temperature, electrons in a superconductor form Cooper pairs, which move without scattering off lattice ions, eliminating resistance as there’s no energy loss to collisions. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields No collisions with lattice,

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