Practice question
Question
What is the work function of a metal if radiation of wavelength 242 nm just ionizes it? ( h = 6.626 × 10â»Â³â´ J s, c = 3.0 × __10POW₈__m s^{-1, N_A = 6.022 × __10POW₂₃__mol^{-1 )
Explanation
Given:
What is the work function of a metal if radiation of wavelength 242 nm just ionizes it? ( h = 6.626 × 10â»Â³â´ J s, c = 3.0 × __10POW₈__m s^{-1, N_A = 6.022 × __10POW₂₃__mol^{-1 )
These values define the system as per NCERT data.
Formula:
Energy per photon = hc/lambda = frac6.626 × 10â»Â³â´ × 3.0 × __10POW₈₂₄₂__ × 10â»â¹= 8.22 × 10â»Â¹â¹ J.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Per mole = 8.22 × 10â»Â¹â¹ × 6.022 × __10POW₂₃__= 494 kJ mol^{-1 .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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