Practice question

MCQ

Question

What is the product when CH₃CH₂CH₂Cl reacts with NaNH₂ in liquid ammonia?

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Choose one · Correct answer highlighted

CH₃CH₂CH₂NH₂ CH₃CH₂CH₃ CH₃CH₂CH₂OH CH₃CH=CH₂ Correct

Explanation

NaNH₂ in liquid ammonia (strong base) promotes elimination (E₂) in CH₃CH₂CH₂Cl , forming CH₃CH=CH₂ (propene).

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