Practice question
Question
What is the orbital period of an electron in the \( n = 4 \) orbit if \( v_1 = 2.2 \times 10^6 \,
\text{m/s} \) and \( r_1 = 5.3 \times 10^{-11} \, \text{m} \)?
Explanation
**Angular momentum** L_n = n h/2π, h=6.6×10⁻³⁴ J·s, L₂=2×6.6×10⁻³⁴/2π=2.11×10⁻³⁴ J·s, speed v_n = e²/(2 ε₀ h) ×1/n ≈2.2×10⁶/n m/s, kinetic energy ½ m v² =13.6/n² eV, illustrating Bohr model predictions for hydrogen-like atoms. v₄ = (2.2 × 10⁶/4) = 5.5 × 10⁵ m/s . r₄ = 16 × 5.3 × 10⁻¹¹ = 8.48 × 10⁻¹⁰ m . T = (2π r₄/v₄) = (2 × 3.14 × 8.48 × 10⁻¹⁰/5.5 × 10⁵) ≈ 9.68 × 10⁻¹⁵ s . Using E_n = -13.6/n² eV, r_n = n² a₀, L = n h/2π, R = R₀ A^¹/³, BE = Δm c² and 1 u = 931.5 MeV, evaluation
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