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Question

What is the orbital period of an electron in the first orbit of a hydrogen atom if its speed is \( 2.2
\times 10^6 \, \text{m/s} \) and radius is \( 5.3 \times 10^{-11} \, \text{m} \)?

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Explanation

**Angular momentum** L_n = n h/2π, h=6.6×10⁻³⁴ J·s, L₂=2×6.6×10⁻³⁴/2π=2.11×10⁻³⁴ J·s, speed v_n = e²/(2 ε₀ h) ×1/n ≈2.2×10⁶/n m/s, kinetic energy ½ m v² =13.6/n² eV, illustrating Bohr model predictions for hydrogen-like atoms. T = (2π r/v) = (2 × 3.14 × 5.3 × 10⁻¹¹/2.2 × 10⁶) ≈ 1.51 × 10⁻¹⁶ s . Using E_n = -13.6/n² eV, r_n = n² a₀, L = n h/2π, R = R₀ A^¹/³, BE = Δm c² and 1 u = 931.5 MeV, evaluation yields 1.51 × 10⁻¹⁶ s, consistent with Bohr model and nuclear binding energy systematics.

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