Practice question
Question
What is the kinetic energy of a 700kg satellite at 9RE from Earth’s center? (ME\=6×1024kg,RE\=6.4×106m,G\=6.67×10−11N m2/kg2)
Explanation
K = GMEm2r. r = 9RE = 5.76×107m. K = 6.67×10−11×6×1024×7002×5.76×107. K = 2.801×10171.152×108≈2.43×109J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 × 10⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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