Practice question
Question
What is the intensity at a point in a double-slit experiment where the path difference is \( 3\lambda/4
\), if the maximum intensity is \( 4I_0 \)?
Explanation
**Phase difference** corresponding to path difference Δ, φ =2π Δ/λ, for Δ=5λ/8 φ=5π/4, for Δ=9λ/4 φ=9π/2, for Δ=λ path difference φ=2π constructive, but for destructive condition path difference λ can be destructive if one reflection introduces π phase shift, resultant amplitude zero when φ=(2n+1)π. Intensity I = 4I₀ cos²(Φ/2) , where Φ = (2π/λ) Δ . For Δ = (3λ/4) , Φ = (2π/λ) · (3λ/4) = (3π/2) , I = 4I₀ cos²((3π/4)) = 4I₀ ((√(2)/2))² = 4I₀ × (1/2) = 2I₀ . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v,
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