Practice question
Question
What is the frequency of light with a wavelength of \( 510 \, \text{nm} \) in air, given the speed of
light in air is \( 3.0 \times 10^8 \, \text{m/s} \)?
Explanation
**Intensity not depend on speed** when enters denser medium because intensity I ∝ n E₀²? Actually Poynting vector S = E×H, energy density u =½ ε E², for same amplitude E₀ intensity proportional to n, but amplitude changes at interface due to reflection, total energy conserved incident = reflected + transmitted, interference does not destroy energy, it redistributes. Frequency nu = (c/λ) . λ = 5.1 × 10⁻⁷ m , c = 3.0 × 10⁸ m/s . nu = (3.0 × 10⁸/5.1 × 10⁻⁷) ≈ 5.88 × 10¹⁴ Hz . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ,
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