Practice question
Question
What is the force on a submarine window (0.05m2) at 600m depth in seawater (ρ\=1.03×103kg/m3), interior at atmospheric pressure? (Take g\=10m/s2)
Explanation
Gauge pressure: Pg = ρgh = 1.03×103×10×600 = 6.18×106Pa. F = PgA = 6.18×106×0.05 = 3.09×105N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.09 × 10⁵ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.