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Question

What is the collision frequency of a gas molecule if its mean free path is 2 × 10⁻⁷ m and average speed is 500 m/s?

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Explanation

**Internal energy of ideal gas** U = f/2 n R T depends only on temperature, f degrees of freedom, n moles, R=8.314 J/mol·K, for monatomic f=3 U=3/2 n R T, diatomic f=5 at moderate T U=5/2 n R T, independent of pressure or volume, only T matters for ideal gas. Collision frequency = ()/(l).(500)/(2 × 10⁻⁷) = 2.5 × 10⁹ s⁻¹. Substituting values gives 2.5 × 10⁹ s⁻¹, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V = n R T and v_rms = √(3 R T/M) relations.

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