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Question

What is the angular momentum of an electron in the \( n = 5 \) state of a hydrogen atom? (Use \( h =
6.6 \times 10^{-34} \, \text{J·s} \))

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Explanation

**Bohr's quantization** angular momentum L = m v r = n h/2π, for n=2 L=2h/2π= h/π=2.11×10⁻³⁴ J·s, for n=5 L=5h/2π, de Broglie λ = h/p, p= m v, for first orbit v=2.2×10⁶ m/s, λ= h/(m v)=6.6×10⁻³⁴/(9.1×10⁻³¹×2.2×10⁶)=3.3×10⁻¹⁰ m, circumference 2πr=3.33×10⁻¹⁰ m, one wavelength fits for n=1. L = n (h/2π) . For n = 5 : L = 5 × (6.6 × 10⁻³⁴/2 × 3.14) ≈ 5.25 × 10⁻³⁴ J·s . Using E_n = -13.6/n² eV, r_n = n² a₀, L = n h/2π, R = R₀ A^¹/³, BE = Δm c² and 1 u = 931.5 MeV, evaluation yields 5.25 × 10⁻³⁴ J·s, consistent with

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