Practice question
Question
Two vectors are given as a\=6i^+3j^ and b\=−4i^+2j^. What is the magnitude of a×b?
Explanation
a×b = |i^j^k^630−420| = k^(6×2−3×(−4)) = k^(12+12) = 24k^. Magnitude = 24. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 24. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.